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For which k is the locus a noncircular, nondegenerate ellipse?

Read the idea, work independently, then explain what changed.

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高二選擇性必修 第一册(A版).pdf · 3.1 · PDF 110 / printed page 105

TOPIC 01

Ellipse: definition, axes and constraints

Build an ellipse from a distance sum, identify its major direction and distinguish a genuine ellipse from boundary loci.

What you will be able to explain

  • Relate the focal definition to a²=b²+c².
  • Read translated and vertical ellipses without confusing denominators with lengths.
  • Use scaling to optimize a linear quantity and test locus feasibility.

Try it. Leave your reasoning visible.

Use one hint at a time. A correction explains what changed, not just the final answer.

Examples 1–3: study a full demonstration; finish a solution from its first step; then choose a method independently before opening the solution. The remaining exercises may continue after class.

01 / Standard#Your turn

For which k is the locus a noncircular, nondegenerate ellipse?

x2/9+y2/k=1x^2/9+y^2/k=1
Skills and prerequisite lessons

Scope: JM01 / JM02

Working and explanation

BUILD THE REASONING

Hint 1
Both denominators must be positive.
Hint 2
Equal denominators give a circle.
Worked solution
  1. Exclude zero and negative k.

    k>0k>0
  2. Exclude the circle while permitting either major-axis direction.

    k≠9k\ne9

k>0 and k≠9.

Checks and common pitfalls: k>9 is also an ellipse; it simply has a vertical major axis.

Reasoning checklist · self / teacher assessment
  • k>0 and k≠9.
  • k>9 is also an ellipse; it simply has a vertical major axis.

Think first. Reveal a hint when the class is ready.

Focus on one question

Teacher preparation and assessment

40-minute lesson

MinutesFocusTeaching and student action
5Prediction and diagnosisPredict the string-and-pins boundary cases.
8Concept derivationDerive the relation between a,b,c from axis vertices.
10Guided applicationRead horizontal, vertical and translated equations.
12Transfer and explanationSolve a scaled optimization and an impossible-locus test.
5Exit evidenceClassify the focal-sum exit cases.

Question sequence

  • What happens when the string length equals the distance between the pins?
  • Which direction has the largest intercept?

Board development

  • Use three rows: sum below, equal to, and above the focal separation.
  • Scale x=2U,y=3V before bounding 3x+4y.

Expected correct and incorrect responses

  • Students always put foci on the x-axis. Ask them to mark the larger intercept first.
  • Correct: “The larger denominator is under y², so the foci lie on the y-axis.”
  • Incorrect: “The denominator 25 means the semiaxis has length 25.”

Follow-up questions

  • Why must an equality case be checked after finding an upper bound?

Remediation

  • Draw semiaxes as actual lengths before calculating c².

Exit check

  • Classify distance sums 5, 6 and 10 for foci at (±3,0).

Assessment checklist and sample responses

  • Credit axis identification, positive-length conditions and an attainable equality case. Sample: 6U+12V≤√180 with U²+V²=1; equality fixes the maximizing point.
    Correct: “The larger denominator is under y², so the foci lie on the y-axis.”

No sign-in. Work stays in this browser. Export before clearing browser data. Written reasoning is assessed with a checklist.

Curriculum and source notes ↗