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Give the distribution of Y=2X+1.

Read the idea, work independently, then explain what changed.

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高三選擇性必修 第三册(A版).pdf · 7.2 · PDF 61 / printed page 56

Revisit first: Conditional and total probability

TOPIC 01

Discrete random variables and distributions

Construct a distribution and compute event probabilities from its support.

What you will be able to explain

  • Construct a distribution and compute event probabilities from its support.
  • Justify the method and check the conditions in a new situation.

Try it. Leave your reasoning visible.

Use one hint at a time. A correction explains what changed, not just the final answer.

01 / Standard#Your turn

Give the distribution of Y=2X+1.

X=0,9;P=1/3,2/3X=0,9;\quad P=1/3,2/3
  • Every probability lies in [0,1]; values and events must not be double-counted.
Skills and prerequisite lessons

Working and explanation

BUILD THE REASONING

Hint 1
List the possible values and probabilities before computing moments.
Hint 2
Map each support value through Y=2X+1.
Worked solution
  1. List the possible values and probabilities before computing moments.

  2. Apply the stated relation and retain its conditions.

    0↦1,9↦190\mapsto1,\quad 9\mapsto19
  3. An injective value transformation keeps the corresponding probabilities.

The requested relation or conclusion is shown below.

Y=1,19;P=1/3,2/3Y=1,19;\quad P=1/3,2/3

Checks and common pitfalls: An injective value transformation keeps the corresponding probabilities.

Reasoning checklist · self / teacher assessment
  • State a valid definition or model and its assumptions.
  • Show the intermediate mathematical relations, not only the final claim.
  • Check exclusions, units or the interpretation of the result.

Think first. Reveal a hint when the class is ready.

Focus on one question

Teacher preparation and assessment

Question sequence

  • Construct a distribution and compute event probabilities from its support.
  • Which condition is essential in discrete random variables and distributions?
  • Can two different outcomes lead to the same random-variable value?

Board plan

  • Defining relation: Construct a distribution and compute event probabilities from its support.
    ∑xP(X=x)=1\sum_xP(X=x)=1
  • Conditions: Every probability lies in [0,1]; values and events must not be double-counted.

Anticipated thinking

  • A random variable value and its probability are not interchangeable.

Assessment checklist

  • 1 mark: choose the correct representation and conditions.
  • 1 mark: establish the intermediate relation.
  • 1 mark: complete a connected calculation or proof.
  • 1 mark: interpret and check the conclusion.

No sign-in. Work stays in this browser. Export before clearing browser data. Written reasoning is assessed with a checklist.

Curriculum and source notes ↗