← Senior Mathematics Studio

LEARN · EXPLAIN · REVISE

Find p when P(X=0)=p, P(X=1)=2p and P(X=2)=tp.

Read the idea, work independently, then explain what changed.

Return to the lesson / paper ↗

高三選擇性必修 第三册(A版).pdf · 7.2 · PDF 61 / printed page 56

Revisit first: Conditional and total probability

TOPIC 01

Discrete random variables and distributions

Construct a distribution and compute event probabilities from its support.

What you will be able to explain

  • Construct a distribution and compute event probabilities from its support.
  • Justify the method and check the conditions in a new situation.

Try it. Leave your reasoning visible.

Use one hint at a time. A correction explains what changed, not just the final answer.

01 / Standard#Worked example

Find p when P(X=0)=p, P(X=1)=2p and P(X=2)=tp.

t=3t=3
  • Every probability lies in [0,1]; values and events must not be double-counted.
Skills and prerequisite lessons

Working and explanation

BUILD THE REASONING

Hint 1
List the possible values and probabilities before computing moments.
Hint 2
Use this intermediate relation.
p+2p+tp=1p+2p+tp=1
Worked solution
  1. List the possible values and probabilities before computing moments.

  2. Apply the stated relation and retain its conditions.

    6p=1⇒p=1/66p=1\Rightarrow p=1/6
  3. Check all resulting probabilities are nonnegative.

The requested value is 0.166666666667.

Checks and common pitfalls: Check all resulting probabilities are nonnegative.

Think first. Reveal a hint when the class is ready.

Focus on one question

Teacher preparation and assessment

Question sequence

  • Construct a distribution and compute event probabilities from its support.
  • Which condition is essential in discrete random variables and distributions?
  • Can two different outcomes lead to the same random-variable value?

Board plan

  • Defining relation: Construct a distribution and compute event probabilities from its support.
    ∑xP(X=x)=1\sum_xP(X=x)=1
  • Conditions: Every probability lies in [0,1]; values and events must not be double-counted.

Anticipated thinking

  • A random variable value and its probability are not interchangeable.

Assessment checklist

  • 1 mark: choose the correct representation and conditions.
  • 1 mark: establish the intermediate relation.
  • 1 mark: complete a connected calculation or proof.
  • 1 mark: interpret and check the conclusion.

No sign-in. Work stays in this browser. Export before clearing browser data. Written reasoning is assessed with a checklist.

Curriculum and source notes ↗