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Reflect P in the line y=x.

Read the idea, work independently, then explain what changed.

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高二選擇性必修 第一册(A版).pdf · 2.3 · PDF 75 / printed page 70

Revisit first: Equations of a line

TOPIC 01

Intersections and distance formulas

Solve intersections and calculate point-line and parallel-line distances with geometric checks.

What you will be able to explain

  • Solve intersections and calculate point-line and parallel-line distances with geometric checks.
  • Justify the method and check the conditions in a new situation.

Try it. Leave your reasoning visible.

Use one hint at a time. A correction explains what changed, not just the final answer.

01 / Transfer#Your turn

Reflect P in the line y=x.

P=(13,2)P=(13,2)
  • The denominator is the norm of the normal vector; parallel-line formulas require matched coefficients.
Skills and prerequisite lessons

Working and explanation

BUILD THE REASONING

Hint 1
Translate the geometric condition into a coordinate equation.
Hint 2
Use this intermediate relation.
P+P′=2HP+P\prime=2H
Worked solution
  1. Translate the geometric condition into a coordinate equation.

  2. Apply the stated relation and retain its conditions.

    H=(7.5,7.5)H=(7.5,7.5)
  3. Apply the stated relation and retain its conditions.

    P′=2H−P=(2,13)P'=2H-P=(2,13)
  4. Reflection across y=x swaps coordinates.

The requested relation or conclusion is shown below.

P′=(2,13)P'=(2,13)

Checks and common pitfalls: Reflection across y=x swaps coordinates.

Reasoning checklist · self / teacher assessment
  • State a valid definition or model and its assumptions.
  • Show the intermediate mathematical relations, not only the final claim.
  • Check exclusions, units or the interpretation of the result.

Think first. Reveal a hint when the class is ready.

Focus on one question

Teacher preparation and assessment

Question sequence

  • Solve intersections and calculate point-line and parallel-line distances with geometric checks.
  • Which condition is essential in intersections and distance formulas?
  • Why does multiplying a line equation by 100 leave its distance formula unchanged?

Board plan

  • Intersection: Solve both linear equations simultaneously and check both.
  • Normalized distance: The denominator is the norm of the normal vector; parallel-line formulas require matched coefficients.
    d=∣Ax0+By0+C∣/A2+B2d=|Ax_0+By_0+C|/\sqrt{A^2+B^2}

Anticipated thinking

  • Subtracting constants before matching parallel-line coefficients gives a wrong distance.

Assessment checklist

  • 1 mark: choose the correct representation and conditions.
  • 1 mark: establish the intermediate relation.
  • 1 mark: complete a connected calculation or proof.
  • 1 mark: interpret and check the conclusion.

No sign-in. Work stays in this browser. Export before clearing browser data. Written reasoning is assessed with a checklist.

Curriculum and source notes ↗