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Find the cosine of the acute angle between the planes.

Read the idea, work independently, then explain what changed.

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高二選擇性必修 第一册(A版).pdf · 1.4 · PDF 31 / printed page 26

Revisit first: Coordinate representation of space vectors

TOPIC 01

Applications of space vectors

Use direction and normal vectors to establish angles, distances and spatial relations.

What you will be able to explain

  • Use direction and normal vectors to establish angles, distances and spatial relations.
  • Justify the method and check the conditions in a new situation.

Try it. Leave your reasoning visible.

Use one hint at a time. A correction explains what changed, not just the final answer.

01 / Foundation#Your turn

Find the cosine of the acute angle between the planes.

n1=(1,1,0),n2=(0,1,1)n_1=(1,1,0),\quad n_2=(0,1,1)
  • Use acute line/plane angles; normals must be nonzero and distances nonnegative.
Skills and prerequisite lessons

Working and explanation

BUILD THE REASONING

Hint 1
Use the dot product to connect coordinates with length or angle.
Hint 2
Use this intermediate relation.
cos⁡θ=∣n1⋅n2∣/(∣n1∣∣n2∣)\cos\theta=|n_1\cdot n_2|/(|n_1||n_2|)
Worked solution
  1. Use the dot product to connect coordinates with length or angle.

  2. Apply the stated relation and retain its conditions.

    n1⋅n2=1n_1\cdot n_2=1
  3. Apply the stated relation and retain its conditions.

    cos⁡θ=1/2\cos\theta=1/2
  4. The angle between normals determines the acute plane angle.

The requested value is 0.5.

Checks and common pitfalls: The angle between normals determines the acute plane angle.

Think first. Reveal a hint when the class is ready.

Focus on one question

Teacher preparation and assessment

Question sequence

  • Use direction and normal vectors to establish angles, distances and spatial relations.
  • Which condition is essential in applications of space vectors?
  • Predict whether translating a plane changes its direction or its distance from a fixed point.

Board plan

  • Normals: A plane normal is perpendicular to every direction in the plane.
    n⋅(X−P)=0n\cdot(X-P)=0
  • Angles and distance: Use acute line/plane angles; normals must be nonzero and distances nonnegative.
    d=∣n⋅(P−P0)∣∣n∣d=\frac{|n\cdot(P-P_0)|}{|n|}

Anticipated thinking

  • The line-plane angle is complementary to the angle between the line direction and plane normal.

Assessment checklist

  • 1 mark: choose the correct representation and conditions.
  • 1 mark: establish the intermediate relation.
  • 1 mark: complete a connected calculation or proof.
  • 1 mark: interpret and check the conclusion.

No sign-in. Work stays in this browser. Export before clearing browser data. Written reasoning is assessed with a checklist.

Curriculum and source notes ↗