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Find the coefficient of e1 when e1=(1,0,0), e2=(1,1,0), e3=(0,0,1).

Read the idea, work independently, then explain what changed.

TOPIC 01

Space vectors and solid geometry: mixed review

A mixed assessment: identify the method, justify it and revise your reasoning.

What you will be able to explain

  • Connect the chapter skills without relying on the order of the exercises.

Try it. Leave your reasoning visible.

Use one hint at a time. A correction explains what changed, not just the final answer.

01 / Foundation#Your turn

Find the coefficient of e1 when e1=(1,0,0), e2=(1,1,0), e3=(0,0,1).

v=(23,2,3)v=(23,2,3)
  • A basis must be independent. Weights representing a point in a plane sum to one.
Skills and prerequisite lessons

Working and explanation

BUILD THE REASONING

Hint 1
Use vector components and the distributive laws.
Hint 2
Use this intermediate relation.
(x+y,y,z)=v(x+y,y,z)=v
Worked solution
  1. Use vector components and the distributive laws.

  2. Apply the stated relation and retain its conditions.

    y=2,z=3,x=23−2=21y=2,\quad z=3,\quad x=23-2=21
  3. Changing the basis changes coefficients even when the geometric vector is unchanged.

The requested value is 21.

Checks and common pitfalls: Changing the basis changes coefficients even when the geometric vector is unchanged.

Think first. Reveal a hint when the class is ready.

Focus on one question

Teacher preparation and assessment

Question sequence

  • Ask students to name the relevant condition before calculating.

Board plan

  • Compare valid methods and annotate their conditions.

Anticipated thinking

  • A correct final value may still hide a missing assumption.

Assessment checklist

  • Check the method, conditions, reasoning and interpretation separately.

No sign-in. Work stays in this browser. Export before clearing browser data. Written reasoning is assessed with a checklist.

Curriculum and source notes ↗