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Quadratic functions, equations and inequalities: mixed assessment

Read the idea, work independently, then explain what changed.

TOPIC 01

Quadratic functions, equations and inequalities: mixed assessment

A mixed assessment: identify the method, justify it and revise your reasoning.

What you will be able to explain

  • Connect the chapter skills without relying on the order of the exercises.

Try it. Leave your reasoning visible.

Use one hint at a time. A correction explains what changed, not just the final answer.

01 / Foundation#Your turn

Solve and justify the sign direction.

−7x>56-7x>56
  • Use the domain, units and sampling assumptions stated in the question.
Skills and prerequisite lessons

Working and explanation

BUILD THE REASONING

Hint 1
Track signs and legal operations before transforming an inequality.
Hint 2
Divide by a negative number.
Worked solution
  1. Track signs and legal operations before transforming an inequality.

  2. Calculate or simplify this relation.

    x<56/(−7)=−8x<56/(-7)=-8
  3. A negative multiplier reverses order.

x<-8.

Checks and common pitfalls: A negative multiplier reverses order.

Reasoning checklist · self / teacher assessment
  • State the relevant definition, condition or model.
  • Show a valid calculation, proof or counterexample.
  • Interpret the conclusion with its restrictions.

Think first. Reveal a hint when the class is ready.

02 / Foundation#Your turn

Positive a,b have sum 14; maximize their product.

  • Use the domain, units and sampling assumptions stated in the question.
Skills and prerequisite lessons

Working and explanation

BUILD THE REASONING

Hint 1
Check nonnegativity, apply AM–GM and verify attainable equality.
Hint 2
Fix the arithmetic mean.
Worked solution
  1. Check nonnegativity, apply AM–GM and verify attainable equality.

  2. Calculate or simplify this relation.

    ab≤((a+b)/2)2=49;a=b=7ab\le((a+b)/2)^2=49;\quad a=b=7
  3. The equal pair satisfies the required sum.

The requested value is 49.

Checks and common pitfalls: The equal pair satisfies the required sum.

Think first. Reveal a hint when the class is ready.

03 / Foundation#Your turn

Calculate the discriminant and interpret its sign.

x2−14x+50=0x^2-14x+50=0
  • Use the domain, units and sampling assumptions stated in the question.
Skills and prerequisite lessons

Working and explanation

BUILD THE REASONING

Hint 1
Find the roots or vertex, then check signs and endpoints.
Hint 2
Use the full coefficient of x.
Worked solution
  1. Find the roots or vertex, then check signs and endpoints.

  2. Calculate or simplify this relation.

    Δ=(−14)2−4(50)=−4\Delta=(-14)^2-4(50)=-4
  3. A negative discriminant means no real root.

The requested value is -4.

Checks and common pitfalls: A negative discriminant means no real root.

Think first. Reveal a hint when the class is ready.

04 / Foundation#Your turn

Give a counterexample to squaring as a general order-preserving rule.

−9<−8-9<-8
  • Use the domain, units and sampling assumptions stated in the question.
Skills and prerequisite lessons

Working and explanation

BUILD THE REASONING

Hint 1
Track signs and legal operations before transforming an inequality.
Hint 2
Compare absolute values.
Worked solution
  1. Track signs and legal operations before transforming an inequality.

  2. Calculate or simplify this relation.

    (−9)2=81>64=(−8)2(-9)^2=81>64=(-8)^2
  3. Squaring is increasing only on nonnegative inputs.

Their squares satisfy 81>64.

Checks and common pitfalls: Squaring is increasing only on nonnegative inputs.

Reasoning checklist · self / teacher assessment
  • State the relevant definition, condition or model.
  • Show a valid calculation, proof or counterexample.
  • Interpret the conclusion with its restrictions.

Think first. Reveal a hint when the class is ready.

05 / Foundation#Your turn

Does the function attain a minimum on this domain?

x+64x,x>8x+\frac{64}x,\quad x>8
  • Use the domain, units and sampling assumptions stated in the question.
Skills and prerequisite lessons

Working and explanation

BUILD THE REASONING

Hint 1
Check nonnegativity, apply AM–GM and verify attainable equality.
Hint 2
The equality point is excluded.
Worked solution
  1. Check nonnegativity, apply AM–GM and verify attainable equality.

  2. Calculate or simplify this relation.

    x+64x−16=(x−8)2x>0x+\frac{64}x-16=\frac{(x-8)^2}{x}>0
  3. Calculate or simplify this relation.

    x→8+⇒x+64x→16x\to8^{+}\Rightarrow x+\frac{64}x\to16
  4. An infimum need not be a minimum.

No; its infimum is 16, approached but not attained.

Checks and common pitfalls: An infimum need not be a minimum.

Reasoning checklist · self / teacher assessment
  • State the relevant definition, condition or model.
  • Show a valid calculation, proof or counterexample.
  • Interpret the conclusion with its restrictions.

Think first. Reveal a hint when the class is ready.

06 / Foundation#Your turn

Find the length of the x-interval where the line is above or on the parabola.

y=(20)x−96,y=x2y=(20)x-96,\quad y=x^2
  • Use the domain, units and sampling assumptions stated in the question.
Skills and prerequisite lessons

Working and explanation

BUILD THE REASONING

Hint 1
Find the roots or vertex, then check signs and endpoints.
Hint 2
Compare their vertical difference.
Worked solution
  1. Find the roots or vertex, then check signs and endpoints.

  2. Calculate or simplify this relation.

    (x−8)(x−12)≤0;(12)−8=4(x-8)(x-12)\le0;\quad (12)-8=4
  3. Interval length is not the count of integer points.

The requested value is 4.

Checks and common pitfalls: Interval length is not the count of integer points.

Think first. Reveal a hint when the class is ready.

07 / Standard#Your turn

Solve both parts and justify the conditions used. Part A: Explain how the sign of a affects multiplying x<b by a. Part B: For which m is this positive for every real x?

A: x<bB: x2−20x+m\begin{gathered}\text{A: }x<b\\\text{B: }x^2-20x+m\end{gathered}
  • Use the domain, units and sampling assumptions stated in the question.
  • Use the domain, units and sampling assumptions stated in the question.
Skills and prerequisite lessons

Working and explanation

BUILD THE REASONING

Hint 1
A: Track signs and legal operations before transforming an inequality.
Hint 2
B: Find the roots or vertex, then check signs and endpoints.
Worked solution
  1. Part A reasoning

  2. Track signs and legal operations before transforming an inequality.

  3. Calculate or simplify this relation.

    ax−ab=a(x−b)ax-ab=a(x-b)
  4. The zero case is different from either strict order.

  5. Part B reasoning

  6. Find the roots or vertex, then check signs and endpoints.

  7. Calculate or simplify this relation.

    x2−20x+m=(x−10)2+m−100x^2-20x+m=(x-10)^2+m-100
  8. Strict positivity requires a strictly positive minimum.

A: If a>0 then ax<ab; if a<0 then ax>ab; if a=0 the results are equal. B: m>100.

Checks and common pitfalls: The zero case is different from either strict order. Strict positivity requires a strictly positive minimum.

Reasoning checklist · self / teacher assessment
  • Solve part A with its stated restrictions.
  • Solve part B using an appropriate representation.
  • Give the reasoning and check conditions in both parts.

Think first. Reveal a hint when the class is ready.

08 / Standard#Your turn

Find the minimum for x>0.

x+81xx+\frac{81}x
  • Use the domain, units and sampling assumptions stated in the question.
Skills and prerequisite lessons

Working and explanation

BUILD THE REASONING

Hint 1
Check nonnegativity, apply AM–GM and verify attainable equality.
Hint 2
The two positive terms have constant product.
Worked solution
  1. Check nonnegativity, apply AM–GM and verify attainable equality.

  2. Calculate or simplify this relation.

    x+81x≥281=18;x=9x+\frac{81}x\ge2\sqrt{81}=18;\quad x=9
  3. Equal terms give an admissible equality case.

The requested value is 18.

Checks and common pitfalls: Equal terms give an admissible equality case.

Think first. Reveal a hint when the class is ready.

09 / Standard#Your turn

Count the integer solutions.

(x+9)(x−11)<0(x+9)(x-11)<0
  • Use the domain, units and sampling assumptions stated in the question.
Skills and prerequisite lessons

Working and explanation

BUILD THE REASONING

Hint 1
Find the roots or vertex, then check signs and endpoints.
Hint 2
Exclude the two integer roots.
Worked solution
  1. Find the roots or vertex, then check signs and endpoints.

  2. Calculate or simplify this relation.

    −9<x<11;(10)−(−8)+1=19-9<x<11;\quad (10)-(-8)+1=19
  3. Strict comparisons exclude equality.

The requested value is 19.

Checks and common pitfalls: Strict comparisons exclude equality.

Think first. Reveal a hint when the class is ready.

10 / Standard#Your turn

Find the least integer greater than every admissible sum a+b.

a<10, b<12a<10,\ b<12
  • Use the domain, units and sampling assumptions stated in the question.
Skills and prerequisite lessons

Working and explanation

BUILD THE REASONING

Hint 1
Track signs and legal operations before transforming an inequality.
Hint 2
Add the upper bounds.
Worked solution
  1. Track signs and legal operations before transforming an inequality.

  2. Calculate or simplify this relation.

    a+b<22a+b<22
  3. Sums approach this bound arbitrarily closely, so no smaller integer works.

The requested value is 22.

Checks and common pitfalls: Sums approach this bound arbitrarily closely, so no smaller integer works.

Think first. Reveal a hint when the class is ready.

11 / Standard#Your turn

Minimize the expression over positive x.

2x+200x2x+\frac{200}x
  • Use the domain, units and sampling assumptions stated in the question.
Skills and prerequisite lessons

Working and explanation

BUILD THE REASONING

Hint 1
Check nonnegativity, apply AM–GM and verify attainable equality.
Hint 2
Include the coefficient two in the product.
Worked solution
  1. Check nonnegativity, apply AM–GM and verify attainable equality.

  2. Calculate or simplify this relation.

    2x+200x≥2400=40;x=102x+\frac{200}x\ge2\sqrt{400}=40;\quad x=10
  3. Equality concerns the complete two terms, not just x and 1/x.

The requested value is 40.

Checks and common pitfalls: Equality concerns the complete two terms, not just x and 1/x.

Think first. Reveal a hint when the class is ready.

12 / Standard#Your turn

For which m is this positive for every real x?

x2−20x+mx^2-20x+m
  • Use the domain, units and sampling assumptions stated in the question.
Skills and prerequisite lessons

Working and explanation

BUILD THE REASONING

Hint 1
Find the roots or vertex, then check signs and endpoints.
Hint 2
Its minimum occurs when the square vanishes.
Worked solution
  1. Find the roots or vertex, then check signs and endpoints.

  2. Calculate or simplify this relation.

    x2−20x+m=(x−10)2+m−100x^2-20x+m=(x-10)^2+m-100
  3. Strict positivity requires a strictly positive minimum.

m>100.

Checks and common pitfalls: Strict positivity requires a strictly positive minimum.

Reasoning checklist · self / teacher assessment
  • State the relevant definition, condition or model.
  • Show a valid calculation, proof or counterexample.
  • Interpret the conclusion with its restrictions.

Think first. Reveal a hint when the class is ready.

13 / Transfer#Your turn

Solve both parts and justify the conditions used. Part A: Does a<b and c<b guarantee a<c? Explain. Part B: Calculate the discriminant and interpret its sign.

B: x2−14x+50=0\begin{gathered}\text{B: }x^2-14x+50=0\end{gathered}
  • Use the domain, units and sampling assumptions stated in the question.
  • Use the domain, units and sampling assumptions stated in the question.
Skills and prerequisite lessons

Working and explanation

BUILD THE REASONING

Hint 1
A: Track signs and legal operations before transforming an inequality.
Hint 2
B: Find the roots or vertex, then check signs and endpoints.
Worked solution
  1. Part A reasoning

  2. Track signs and legal operations before transforming an inequality.

  3. Calculate or simplify this relation.

    a=13, c=12, b=14a=13,\ c=12,\ b=14
  4. Transitivity requires a chain, not merely a shared upper bound.

  5. Part B reasoning

  6. Find the roots or vertex, then check signs and endpoints.

  7. Calculate or simplify this relation.

    Δ=(−14)2−4(50)=−4\Delta=(-14)^2-4(50)=-4
  8. A negative discriminant means no real root.

A: No; the two values below b may occur in either order. B: The requested value is -4.

Checks and common pitfalls: Transitivity requires a chain, not merely a shared upper bound. A negative discriminant means no real root.

Reasoning checklist · self / teacher assessment
  • Solve part A with its stated restrictions.
  • Solve part B using an appropriate representation.
  • Give the reasoning and check conditions in both parts.

Think first. Reveal a hint when the class is ready.

14 / Transfer#Your turn

Minimize the sum of two positive numbers with this product.

ab=144ab=144
  • Use the domain, units and sampling assumptions stated in the question.
Skills and prerequisite lessons

Working and explanation

BUILD THE REASONING

Hint 1
Check nonnegativity, apply AM–GM and verify attainable equality.
Hint 2
With fixed product, AM–GM gives a lower sum bound.
Worked solution
  1. Check nonnegativity, apply AM–GM and verify attainable equality.

  2. Calculate or simplify this relation.

    a+b≥2ab=24;a=b=12a+b\ge2\sqrt{ab}=24;\quad a=b=12
  3. Give an equality pair to prove attainment.

The requested value is 24.

Checks and common pitfalls: Give an equality pair to prove attainment.

Think first. Reveal a hint when the class is ready.

15 / Transfer#Your turn

Solve the quadratic inequality.

(x−11)(x−14)≤0(x-11)(x-14)\le0
  • Use the domain, units and sampling assumptions stated in the question.
Skills and prerequisite lessons

Working and explanation

BUILD THE REASONING

Hint 1
Find the roots or vertex, then check signs and endpoints.
Hint 2
The upward-opening quadratic is nonpositive between its roots.
Worked solution
  1. Find the roots or vertex, then check signs and endpoints.

  2. Calculate or simplify this relation.

    11≤x≤1411\le x\le14
  3. The non-strict comparison includes both roots.

x∈[11,14].

Checks and common pitfalls: The non-strict comparison includes both roots.

Reasoning checklist · self / teacher assessment
  • State the relevant definition, condition or model.
  • Show a valid calculation, proof or counterexample.
  • Interpret the conclusion with its restrictions.

Think first. Reveal a hint when the class is ready.

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