Translate real-input restrictions into inequalities, intervals and open or closed endpoints.
Paint the allowed inputs
Paper starting model
Drag a handle or select an object, then tap its destination.
Painted set: [0, 4). Infinity is a direction and always uses an open bracket.
Give your reason before checking.
Numeric readings
Values in this design
x
In painted set
Allowed by source target
2
yes
yes
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Chapter 3 · Functions
Writing allowed inputs with intervals
Class ______ Name __________________ Date __________
What changes when an endpoint is included, and can infinity be included?
My prediction and reason
Predict whether x = 2 is allowed in 1/(x − 2), and whether x = 3 is allowed in √(x − 3). Explain why the two boundary decisions differ.
Evidence and observations
For 1/(x − 2), test x = 1, 2, 3. Mark 2 with an open point and shade both allowed sides.
For √(x − 3), test x = 2, 3, 4. Mark 3 with a closed point and shade the allowed side.
Write each domain in words, inequalities and interval notation. Check that all three forms make the same endpoint decision.
Explain or give a counterexample
Transfer
Write the domain of √(5 − x), then exclude x = 2 as an extra restriction. Show the included endpoint and excluded point correctly on a number line.
Exit task
Write the domain of 1/(x + 1), and say whether −1 is included. Write the domain of √(x + 1), and say whether −1 is included.
Chapter 3 · Functions · Teacher reference
Writing allowed inputs with intervals
3.1.1(第3課時) · 03_用區間寫出允許的輸入.docx
5 min predict boundary values; 12 min test and draw intervals; 8 min connect notation; 12 min paper practice; 3 min exit check.
What changes when an endpoint is included, and can infinity be included?
Predict whether x = 2 is allowed in 1/(x − 2), and whether x = 3 is allowed in √(x − 3). Explain why the two boundary decisions differ.
Evidence tasks
For 1/(x − 2), test x = 1, 2, 3. Mark 2 with an open point and shade both allowed sides.
For √(x − 3), test x = 2, 3, 4. Mark 3 with a closed point and shade the allowed side.
Write each domain in words, inequalities and interval notation. Check that all three forms make the same endpoint decision.
Reference reasoning
A real denominator cannot equal zero, so 1/(x − 2) allows all real x except 2. A real square root allows a zero radicand, so √(x − 3) allows x ≥ 3. Round brackets exclude a finite endpoint; square brackets include it. Infinity describes an unbounded direction, not an attainable endpoint, so it always takes a round bracket.
Find the natural real domain of the reciprocal expression.
f(x)=x−21
The denominator restriction is x − 2 ≠ 0, hence x ≠ 2.
The domain is (−∞, 2) ∪ (2, ∞). The point 2 is excluded.
Find the natural real domain of the square-root expression.
f(x)=x−3
For a real square root, x − 3 ≥ 0, so x ≥ 3.
The domain is [3, ∞). Input 3 is allowed and gives output 0.
Transfer and exit task
Write the domain of √(5 − x), then exclude x = 2 as an extra restriction. Show the included endpoint and excluded point correctly on a number line.
Write the domain of 1/(x + 1), and say whether −1 is included. Write the domain of √(x + 1), and say whether −1 is included.
The reciprocal domain is (−∞, −1) ∪ (−1, ∞), excluding −1. The square-root domain is [−1, ∞), including −1.
Uses ≠ 0 for a denominator and ≥ 0 for a square-root radicand.
Matches interval brackets to the endpoint decisions and uses round brackets at infinity.
Questions
Is zero forbidden as an output, or only as this denominator?
Can you name the last real number before infinity?
Expected responses
Students often exclude the square-root boundary. Substitute it to obtain √0 = 0.
Some will use a closed bracket at infinity; explain that there is no final real endpoint.
Confusions
x ≠ 2 is two intervals joined by union, not one interval containing 2.
A test table illustrates the restriction but does not replace solving it for all real inputs.
Board plan
Denominator ≠ 0; square-root radicand ≥ 0.
Open point ↔ round bracket; closed point ↔ square bracket.